网站备案更改,中国十大it培训机构排名,苏州前十名传媒公司,电子商务网站建设系统功能我正在尝试在Python 3.3中创建一个简单的程序,该程序采用四个名称的列表,并将它们随机分配给列表中的另一个人.例如,如果名称是John,Aaron,Lydia和Robin#xff1a;
约翰先走,然后选择一个名字.他不能画自己的东西.如果他这样做,他会把它放回去并再次抽签.说约翰画了罗宾的名字…我正在尝试在Python 3.3中创建一个简单的程序,该程序采用四个名称的列表,并将它们随机分配给列表中的另一个人.例如,如果名称是John,Aaron,Lydia和Robin
约翰先走,然后选择一个名字.他不能画自己的东西.如果他这样做,他会把它放回去并再次抽签.说约翰画了罗宾的名字.罗宾的名字将从游泳池中淘汰.接下来是亚伦的抽奖.他画约翰.约翰的名字被淘汰了.等等,直到分配了所有名称.
我创建了一个具有四个名称的列表,并为每个名称分配了一个值1-4.但是,从列表中删除时我遇到了一个问题,说该值不存在.
list.remove(x)x不在列表中.
它看起来像这样
def drawNames():
import random
John1
Aaron2
Lydia3
Robin4
validNames[John, Aaron, Lydia, Robin]
nameDrawnrandom.choice(validNames)
def draw():
nameDrawnrandom.choice(validNames)
#Johns Draw:
draw()
if nameDrawn ! 1:
if nameDrawn 2:
print(John drew: Aaron)
validNames.remove(2)
elif nameDrawn 3:
print(John drew: Lydia)
validNames.remove(3)
elif nameDrawn 4:
print(John drew: Robin)
validNames.remove(4)
#Aarons Draw:
draw()
if nameDrawn !2:
if nameDrawn 1:
print(Aaron drew: John)
validNames.remove(1)
elif nameDrawn 3:
print(Aaron drew: Lydia)
validNames.remove(3)
elif nameDrawn 4:
print(Aaron drew: Robin)
validNames.remove(4)
#Lydias Draw:
draw()
if nameDrawn !3:
if nameDrawn 1:
print(Lydia drew: John)
validNames.remove(1)
elif nameDrawn 2:
print(Lydia drew: Aaron)
validNames.remove(2)
elif nameDrawn 4:
print(Lydia drew: Robin)
validNames.remove(4)
#Robins Draw:
draw()
if nameDrawn !4:
if nameDrawn 1:
print(Robin drew: John)
validNames.remove(1)
elif nameDrawn 2:
print(Robin drew: Aaron)
validNames.remove(2)
elif nameDrawn 3:
print(Robin drew: Lydia)
validNames.remove(3)
drawNames()
我也尝试过使用名称而不是数字值,这会产生相同的错误.
我也觉得这是一个低效的方案.如果您有更好的建议,我将非常有义务.
解决方法:
使用下面的代码,可能会获得更好的里程与上面提供的名称相比,它可以扩展到许多名称.
import copy
import random
validNames[John, Aaron, Lydia, Robin]
def drawNames(namelist,currentname):namelist: list of names to draw from
currentname: name of person doing the current drawdraw_namelist copy.copy(namelist) # make a copy to remove person drawing if needed
if currentname in draw_namelist: # check if the person drawing is in the list
draw_namelist.remove(currentname) # remove current name if in list
try:
drawn_name random.choice(draw_namelist)
namelist.remove(drawn_name)
newnamelist namelist
print Drew {}.format(drawn_name)
print New list: {}.format(newnamelist)
except:
print Nobody for me to draw!
drawn_nameNone
newnamelist namelist
return drawn_name, newnamelist
然后可以按以下方式工作
In [39]: newlist[John, Aaron, Lydia, Robin]
In [40]: name,newlist drawNames(newlist,Lydia)
Drew Robin
New list: [John, Aaron, Lydia]
In [41]: name,newlist drawNames(newlist,John)
Drew Aaron
New list: [John, Lydia]
In [42]: name,newlist drawNames(newlist,Aaron)
Drew John
New list: [Lydia]
In [43]: name,newlist drawNames(newlist,Robin)
Drew Lydia
New list: []
标签python-3-x,list,scripting,python
来源 https://codeday.me/bug/20191122/2059453.html
