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实验的测试方法主要有2个#xff1a;
进入到Xv6系统中#xff0c;执行相应的命令使用实验提供的评分测试 对于单个实验#xff0c;可以使用 make GRADEFLAGSapplication grade其中application为要测试的实验应用#xff0c;例如sleep实验对应的评分测试命令…实验测试方法
实验的测试方法主要有2个
进入到Xv6系统中执行相应的命令使用实验提供的评分测试 对于单个实验可以使用 make GRADEFLAGSapplication grade其中application为要测试的实验应用例如sleep实验对应的评分测试命令为 make GRADEFLAGSsleep grade;对于整个实验可以直接使用 make grade 进行评测
对于Lab1的评分测试感觉不太稳定多次测试中会随机出现测试失败的情况但是根据失败的测试样例进入到Xv6中模拟测试又没发现什么错误。换了机器测试又没这种情况了或许与测试环境有关或者是Xv6在返回结果的过程中引入了其他未知问题暂时找不到原因不纠结这个了还是干正事要紧。 已做的练习提交到github中可以自行拉取并切换到相应的分支查看。https://github.com/kk140906/mit6s081_labs.git 。
sleep(easy) Implement the UNIX program sleep for xv6; your sleep should pause for a user-specified number of ticks. A tick is a notion of time defined by the xv6 kernel, namely the time between two interrupts from the timer chip. Your solution should be in the file user/sleep.c. user/sleep.c
#include kernel/types.h
#include user/user.hint main(int argc ,char **argv) {if (argc ! 2) {const char *info sleep take one argument.\n;write(2,info,strlen(info));exit(1);}int ticks atoi(argv[1]);sleep(ticks);exit(0);
}更改 Makefile
Makefile位于xv6-labs-2020实验的根目录下打开后定位到 “UPROGS\” 在最后添加 “$U/_sleep\”。
pingpong(easy) Write a program that uses UNIX system calls to ‘‘ping-pong’’ a byte between two processes over a pair of pipes, one for each direction. The parent should send a byte to the child; the child should print “: received ping”, where is its process ID, write the byte on the pipe to the parent, and exit; the parent should read the byte from the child, print “: received pong”, and exit. Your solution should be in the file user/pingpong.c user/pingpong.c
#include kernel/types.h
#include user/user.hint main(int argc, char** argv)
{int p[2];char buf[512] { 0 };pipe(p);if (fork() 0 read(p[0], buf, sizeof(buf) - 1) 1) {printf(%d: received ping\n, getpid());// printf(%s\n, buf);write(p[1], c, 1);close(p[0]);close(p[1]);exit(0);}write(p[1], p, 1);wait(0);if (read(p[0], buf, sizeof(buf) - 1) 1)printf(%d: recieved pong\n, getpid());// printf(%s\n, buf);close(p[0]);close(p[1]);exit(0);
}更改 Makefile
Makefile位于xv6-labs-2020实验的根目录下打开后定位到 “UPROGS\” 在最后添加 “$U/_pingpong\”。
primes(moderate/hard) Write a concurrent version of prime sieve using pipes. This idea is due to Doug McIlroy, inventor of Unix pipes. The picture halfway down this page and the surrounding text explain how to do it. Your solution should be in the file user/primes.c. user/primes.c
#include kernel/types.h
#include user/user.h#define MAX_PRIMES 35void pipeline(int fd) {int prime;// 进入管线中时先读一次把这一次的数值作为当前管线的处理的基础数值if (read(fd, prime, sizeof(int)) 0) {close(fd);exit(1); }printf(prime %d\n, prime);int p[2] {-1};pipe(p);if (fork() 0) {close(p[1]);pipeline(p[0]);exit(0);}close(p[0]);int val;while (read(fd, val, sizeof(int))) {if (val % prime 0)continue;write(p[1], val, sizeof(int));}close(fd);close(p[1]);wait(0);exit(0);
}int main(int argc, char **argv) {int p[2] {-1};pipe(p);if (fork() 0) {// xv6 资源不多能提前关闭的文件描述符都需要提前关闭close(p[1]);// p[0] 在管线中关闭pipeline(p[0]);exit(0);}close(p[0]);for (int i 2; i MAX_PRIMES; i) {write(p[1], i, sizeof(int));}close(p[1]);wait(0);exit(0);
}更改 Makefile
Makefile位于xv6-labs-2020实验的根目录下打开后定位到 “UPROGS\” 在最后添加 “$U/_primes\”。
find (moderate) Write a simple version of the UNIX find program: find all the files in a directory tree with a specific name. Your solution should be in the file user/find.c. user/find.c
#include kernel/types.h
#include kernel/fcntl.h
#include kernel/fs.h
#include kernel/stat.h
#include user/user.h#define MAX_PATH_LEN 256
typedef enum { false, true } bool;
bool match(const char *dirs, const char *file) {const char *p dirs strlen(dirs);char formated_dirs[MAX_PATH_LEN];while (*p ! /)p--;strcpy(formated_dirs, p);return !strcmp(formated_dirs, file);
}void find(char *dir, const char *file) {int fd;if ((fd open(dir, O_RDONLY)) 0) {fprintf(2, find: cannot open %s\n, dir);return;}struct stat st;if (fstat(fd, st) 0) {fprintf(2, find: cannot stat %s\n, dir);close(fd);return;}char dirs[MAX_PATH_LEN] {0};struct dirent de;char *p;switch (st.type) {case T_DIR:strcpy(dirs, dir);p dirs strlen(dirs);*p /;while (read(fd, de, sizeof(de)) sizeof(de)) {// 不再继续处理 . 和 .. 目录if (de.inum 0 || !strcmp(de.name,.) || !strcmp(de.name,..))continue;memmove(p, de.name, DIRSIZ);p[DIRSIZ] 0;if (stat(dirs, st) 0) {fprintf(2, find: cannot stat %s\n, dir);close(fd);}if (st.type T_FILE match(dirs, file)) {printf(%s\n, dirs);} else if (st.type T_DIR dirs[strlen(dirs) - 1] ! . ) {find(dirs, file);}}break;default:break;}
}int main(int argc, char **argv) {if (argc ! 3) {fprintf(2, usage: find [dir] [file].);exit(1);}find(argv[1], argv[2]);exit(0);
}更改 Makefile
Makefile位于xv6-labs-2020实验的根目录下打开后定位到 “UPROGS\” 在最后添加 “$U/_find\”。
xargs (moderate) Write a simple version of the UNIX xargs program: read lines from the standard input and run a command for each line, supplying the line as arguments to the command. Your solution should be in the file user/xargs.c. user/xargs.c
#include kernel/param.h
#include kernel/types.h
#include user/user.hint getline(char *buf) {char c;char *s buf;while (read(0, c, 1) 1 c ! \n) {*buf c;}return strlen(s);
}int main(int argc, char **argv) {if (argc 2) {fprintf(2, xargs take one argument at least.);exit(1);}char *args[MAXARG];for (int i 0; i argc - 1; i) {args[i] argv[i 1];}char buf[MAXPATH] {0};while (getline(buf)) {args[argc - 1] buf;args[argc] 0;if (fork() 0) {exec(argv[1], args);exit(0);}wait(0);memset(buf, 0, MAXPATH);}exit(0);
}更改 Makefile
Makefile位于xv6-labs-2020实验的根目录下打开后定位到 “UPROGS\” 在最后添加 “$U/_xargs\”。
原文地址https://blog.nas-kk.top/?p385
